A) 10cm
B) \[10\sqrt{2}\]cm
C) 20cm
D) \[5\sqrt{2}\] cm
Correct Answer: B
Solution :
Radius of path, \[r=\frac{1}{B}\sqrt{\frac{2mV}{q}}\] \[\therefore \] \[\frac{{{r}_{\alpha }}}{{{r}_{p}}}=\sqrt{\frac{{{m}_{\alpha }}}{{{m}_{p}}}}\sqrt{\frac{{{q}_{p}}}{{{q}_{\alpha }}}}\] \[\therefore \] \[\frac{{{r}_{\alpha }}}{10}=\sqrt{\frac{4}{2}}\] \[{{r}_{\alpha }}=10\sqrt{2}cm\]
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