A) Helium
B) Lithium
C) Protium
D) Tritium
Correct Answer: C
Solution :
| Atom | Neutron in the nucleus (atomic mass-atomic number) |
| \[_{2}H{{e}^{4}}\](Helium) | 2 |
| \[_{3}L{{i}^{7}}\](Lithium) | 4 |
| \[_{1}{{H}^{1}}\](protium) | 0 |
| \[_{1}{{H}^{3}}\](Tritium) | 2 |
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