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Uttarakhand PMT Uttarakhand PMT Solved Paper-2010

  • question_answer
    For a gene with two alleles, if the gene frequency of recessive gene is 0.2. What is the genotypic frequency of homozygous dominant?

    A)  0.064          

    B)  0.8

    C)  0.64            

    D)  0.32

    Correct Answer: C

    Solution :

    According to Hardy-Weinberg law, the allelic frequency \[{{\left( A+a \right)}^{2}}=1\] or            \[A+a=1\] and for genetic frequency \[{{A}^{2}}+2Aa+{{a}^{2}}=1\] where A = The frequency of dominant allele and a = The frequency of recessive allele In the question, \[a=0.2\] So,          \[A+0.2=1\] \[A=0.8\] So, the genotypic frequency of homozygous dominant \[AA=0.8\times 0.8=0.64.\]


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