A) 50%
B) 75%
C) 100%
D) 60%
Correct Answer: B
Solution :
Number of half-lives, \[n=\frac{10}{5}=2\] Remaining amount, \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] \[={{N}_{0}}{{\left( \frac{1}{2} \right)}^{2}}=\frac{{{N}_{0}}}{4}\] \[\frac{N}{{{N}_{0}}}=\frac{1}{4}\times 100=25%\] Probability of decay \[=(100-25)%=75%\]
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