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Uttarakhand PMT Uttarakhand PMT Solved Paper-2011

  • question_answer
    The transfer ratio \[\beta \] of a transistor is 50. The input resistance of the transistor when used in the common emitter mode is 1 k\[\Omega \]. The peak value of the collector alternating current for an input peak voltage of 0.01 V is

    A)  0.25 \[\mu A\]         

    B)  0.01 \[\mu A\]

    C)  500 \[\mu A\]          

    D)  100 \[\mu A\]

    Correct Answer: C

    Solution :

     Input current \[=\frac{{{V}_{i}}}{{{R}_{i}}}=\frac{0.01}{{{10}^{3}}}\] \[={{10}^{-5}}A\] Output collector current \[=\beta \times input\text{ }current\] \[=50\times {{10}^{-5}}A\] \[=500\mu A\]


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