A) 50 \[\mu F\]
B) 25 \[\mu F\]
C) 100 \[\mu F\]
D) 12.5 \[\mu F\]
Correct Answer: D
Solution :
Energy stored in capacitor is equal to energy stored in inductance \[\frac{1}{2}c{{v}^{2}}=\frac{1}{2}L{{I}^{2}}\] \[c=\frac{L{{I}^{2}}}{{{V}^{2}}}\] \[=\frac{1\times {{(2)}^{2}}}{{{(400)}^{2}}}\] \[=25\,\mu F\]
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