A) \[{{(C{{H}_{3}})}_{2}}C=CHC{{H}_{3}}\]
B) \[C{{H}_{3}}CH=CHC{{H}_{3}}\]
C) \[{{(C{{H}_{3}})}_{2}}CHCH=C{{H}_{2}}\]
D) \[{{(C{{H}_{3}})}_{2}}C=C{{H}_{2}}\]
Correct Answer: A
Solution :
\[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{2}}OH\xrightarrow[{}]{{}}C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,=CH-C{{H}_{3}}\] \[\underset{\begin{smallmatrix} 1{}^\circ carbonium\text{ }ion \\ \,\,\,(less\text{ }stable) \end{smallmatrix}}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-\overset{+}{\mathop{C}}\,{{H}_{2}}}}\,\xrightarrow[{}]{1,2-methyl\text{ }shift}\] \[\underset{\begin{smallmatrix} 3{}^\circ carbonium\text{ }ion \\ \,\,\,\,(more\text{ }stable) \end{smallmatrix}}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{2}}-C{{H}_{3}}}}\,\] \[\downarrow -{{H}^{+}}\] \[C{{H}_{3}}-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}\,=CH-C{{H}_{3}}\]
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