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Uttarakhand PMT Uttarakhand PMT Solved Paper-2011

  • question_answer
    In the cell,\[Zn|Z{{n}^{2+}}({{C}_{1}})||C{{u}^{2+}}({{C}_{2}})|Cu\] \[{{E}_{cell}}-E_{cell}^{o}=0.0591\,V.\]The ratio\[\frac{{{C}_{1}}}{{{C}_{2}}}\]at 298 K will be

    A)  2     

    B)  \[{{10}^{-2}}\]  

    C)  1     

    D)  100

    Correct Answer: B

    Solution :

     \[Zn+C{{u}^{2+}}\xrightarrow[{}]{{}}Z{{n}^{2+}}+Cu\] \[{{E}_{cell}}-E_{cell}^{o}=-\frac{0.0591}{2}\log \frac{[Z{{n}^{2+}}]}{[C{{u}^{2+}}]}\] \[0.0591=-\frac{0.0591}{2}\log \frac{{{C}_{1}}}{{{C}_{2}}}\] \[\log \frac{{{C}_{1}}}{{{C}_{2}}}=-2\] \[\frac{{{C}_{1}}}{{{C}_{2}}}=Anti\log \overline{2}={{10}^{-2}}\]


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