A) \[{{(C{{H}_{3}})}_{2}}CH-CHO\]
B) \[HCHO\]
C) \[{{C}_{6}}{{H}_{5}}CHO\]
D) \[C{{H}_{3}}CHO\]
Correct Answer: A
Solution :
Since, 2-methyl propanal contains one\[\alpha -H,\] it undergoes aldol condensation. Surprisingly, it also undergoes cannizaro reaction. \[2{{(C{{H}_{3}})}_{2}}CHCHO\xrightarrow[473\,K]{NaOH}{{(C{{H}_{3}})}_{2}}CHCOONa\] \[+{{(C{{H}_{3}})}_{2}}CH-C{{H}_{2}}OH\]
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