A) ethyl formate
B) acetyl chloride
C) carbon dioxide
D) ethyl chloroformate
Correct Answer: D
Solution :
\[C{{H}_{3}}MgBr+\underset{ethyl\text{ }chloro\text{ }formate}{\mathop{Cl-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-O{{C}_{2}}{{H}_{5}}}}\,\xrightarrow[{}]{{}}\] \[\left[ Cl-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} OMGBr \\ | \end{smallmatrix}}{\mathop{C}}}\,-O{{C}_{2}}{{H}_{5}} \right]\xrightarrow[{}]{{}}\underset{ethyl\text{ }acetate}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-O{{C}_{2}}{{H}_{5}}}}\,\]
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