A) \[S{{O}_{2}}\]
B) \[{{H}_{2}}O\]
C) \[N{{H}_{3}}\]
D) \[SO_{4}^{2-}\]
Correct Answer: A
Solution :
\[S{{O}_{2}}\]has\[s{{p}^{2}}-\]hybridisation of S-atom. All other species (\[{{H}_{2}}O,N{{H}_{3}}\]and\[SO_{4}^{2-}\]) have\[s{{p}^{3}}\]hybridisation.
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