A) \[\overline{\text{A}}\cdot \overline{\text{B}}\]
B) \[\overline{\text{A}}+\overline{\text{B}}\]
C) \[\text{A}\cdot \text{B}\]
D) \[\text{A+B}\]
Correct Answer: D
Solution :
According to De-Morgans theorem \[\overline{A}.\,\,\overline{B}=(\overline{A+B})\] \[\therefore \] \[(\overline{\overline{A}.\overline{B}})=(\overline{\overline{A+B)}}\] \[=(A+B)\] \[(\because \,\,\,\overline{\overline{A}}=A)\] \[\therefore \] \[(\overline{\overline{A}.\,\,\,\overline{B}})=(A+B)\]
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