A) \[_{52}^{137}Te\]
B) \[_{55}^{144}Cs\]
C) \[_{56}^{137}Ba\]
D) \[_{56}^{144}Ba\]
Correct Answer: D
Solution :
\[_{92}^{235}U+_{0}^{1}n\xrightarrow{{}}_{36}^{90}Kr+_{56}^{144}Ba+2_{0}^{1}n\] Note: In the nuclear reaction atomic number and mass are conserved.
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