A) \[342.3g\]
B) \[9.91\times {{10}^{23}}\]
C) \[11\times {{10}^{23}}\]
D) \[44\times {{10}^{23}}H\]atoms
Correct Answer: B
Solution :
\[Mole\,\,of\,\,sucrose=\frac{mass\,\,of\,\,sucrose\,(in\,gram)}{molecular\,\,weight\,\,of\,\,sucrose}\] \[=\frac{25.6}{342.3}=0.0747882\] Formula of sucrose \[={{C}_{12}}{{H}_{22}}{{O}_{11}}\] Number of H atoms in one mole of sucrose = 22 Number of H atoms in 25.6 g of sucrose \[=22\times 0.074788\times 6.023\times {{10}^{23}}\] \[=9.9\times {{10}^{23}}\]
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