VIT Engineering VIT Engineering Solved Paper-2008

  • question_answer
    The molar conductivities of \[KCl,Nacl\] and \[KN{{O}_{3}}\] are 152, 128 and \[111\,\,S\,\,\,c{{m}^{2}}\,\,mo{{l}^{-1}}\] respectively. What is the molar conductivity of \[NaN{{O}_{3}}\]?

    A)  \[101\,\,S\,c{{m}^{2}}mo{{l}^{-1}}\]

    B)  \[87S\,c{{m}^{2}}\,mo{{l}^{-1}}\]

    C)  \[-101S\,c{{m}^{2}}\,mo{{l}^{-1}}\]

    D)  \[-391\,\,S\,c{{m}^{2}}\,mo{{l}^{-1}}\]

    Correct Answer: B

    Solution :

     \[NaCl+KN{{O}_{3}}\xrightarrow{{}}NaN{{O}_{3}}+KCl\] \[KCl-NaCl\] Molar conductivities 152     128 difference \[=24S\,\,c{{m}^{2}}mo{{l}^{-1}}\] Molar conductivities of \[KN{{O}_{3}}=111\] Molar conductivities of \[NaN{{O}_{3}}\] \[=111-24=87\,S\,c{{m}^{2}}mo{{l}^{-1}}\]


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