A) \[x-\frac{4}{3}=0\]
B) \[x+\frac{1}{4}=0\]
C) \[x-\frac{3}{4}=0\]
D) \[x-\frac{1}{4}=0\]
Correct Answer: D
Solution :
The equation of parabola is \[{{y}^{2}}+4x+3=0\] \[\Rightarrow \] \[{{y}^{2}}=-\,4\left( x+\frac{3}{4} \right)\] Let \[X=x+\frac{3}{4}\]and \[Y=y\] \[\therefore \]Equation of parabola becomes \[{{Y}^{2}}=-\,4X\] The equation of directrix of parabola is \[X=1\] \[(\because a=1)\] \[\Rightarrow \] \[x+\frac{3}{4}=1\] \[\Rightarrow \] \[x-\frac{1}{4}=0\]
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