A) \[s\to \,\tilde{\ }q\]
B) \[\tilde{\ }q\to s\]
C) \[\tilde{\ }s\to \,\tilde{\ }q\]
D) \[q\to \,\tilde{\ }s\]
Correct Answer: B
Solution :
\[\because \]\[p\to q\to r\to p\]and\[\tilde{\ }s\to r\]| \[\text{s}\] | \[\text{q}\] | \[\text{r}\] | \[\text{ }\!\!\tilde{\ }\!\!\text{ }\,\text{s}\] | \[\text{ }\!\!\tilde{\ }\!\!\text{ }\,\text{q}\] | \[\text{r}\] | \[\tilde{\ }s\to r\] | \[\tilde{\ }s\to s\] |
| T | T | T | T | F | T | T | T |
| T | F | T | T | T | T | T | T |
| F | T | T | F | F | T | F | F |
| F | F | T | F | T | T | T | T |
| T | T | F | T | F | F | T | T |
| T | F | F | T | T | F | T | T |
| F | T | F | F | F | F | F | F |
| F | F | F | F | T | F | T | T |
You need to login to perform this action.
You will be redirected in
3 sec
