A) \[\frac{1}{5}\]
B) \[\frac{1}{10}\]
C) \[\frac{3}{20}\]
D) \[\frac{1}{20}\]
Correct Answer: C
Solution :
Given, \[{{x}^{2}}-n=0\] \[\Rightarrow \] \[x\pm \sqrt{n}\] \[\therefore \,\,n=\]1, 4, 9,16, 25, 36 \[\therefore \] Required probability\[=\frac{6}{40}=\frac{3}{20}\]You need to login to perform this action.
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