A) 4
B) 2
C) 0
D) 1
Correct Answer: B
Solution :
\[{{x}^{4}}+\sqrt{{{x}^{4}}+20}=22\] \[\Rightarrow \]\[{{x}^{4}}+20+\sqrt{{{x}^{4}}+20}=22+20\] \[\Rightarrow \]\[({{x}^{4}}+20)+\sqrt{{{x}^{4}}+20}=44\] Let \[\sqrt{{{x}^{4}}+20}=y\] \[\therefore \]\[{{y}^{2}}+y-44=0\] Hence, the number of real roots of the equation is 2.You need to login to perform this action.
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