| (i) \[{{y}_{1}}\,=a\,\sin \,(\omega t+{{\phi }_{1}})\] |
| (ii) \[{{y}_{2}}\,=a\,\sin \,2\omega t\] |
| (iii) \[{{y}_{3}}\,={{a}^{}}\,\sin \,(\omega t+{{\phi }_{2}})\] |
| (iv) \[{{y}_{4}}\,={{a}^{}}\,\sin \,(3\omega t+\phi )\] |
A) (i) and (ii)
B) (ii) and (iii)
C) (i) and (iii)
D) (iii) and (iv)
Correct Answer: C
Solution :
Interference phenomenon takes place between two waves which have equal frequency and propagate in same direction. Hence, \[{{y}_{1}}=a\sin (\omega t+{{\phi }_{1}})\] \[{{y}_{3}}=a\sin (\omega t+{{\phi }_{2}})\] will give rise to interference as the two waves have same frequency co.
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