A) \[{{H}_{3}}C-C{{H}_{2}}-C\equiv CH\]
B) \[{{H}_{2}}C=CH-C\equiv CH\]
C) \[HC\equiv C-C{{H}_{2}}-C\equiv CH\]
D) \[NaOH\]
Correct Answer: A
Solution :
From de-Broglies equation \[25:9\] \[25:9\] \[\Delta {{H}_{f}}(H)=218kJ/mol\] \[H-H\] \[52.15\] \[911\] \[104\] \[52153\] \[Alkyne\xrightarrow[Lindlars\,\,catalyst]{{{H}_{2}}}A\xrightarrow{Ozonolysis}\underset{only}{\mathop{B}}\,\] \[\xleftarrow[\Pr ocess]{Wac\ker }C{{H}_{2}}=C{{H}_{2}}\] \[{{H}_{3}}C-C\equiv C-C{{H}_{3}}\] \[{{H}_{3}}C-C{{H}_{2}}-C\equiv CH\] \[{{H}_{2}}C=CH-C\equiv CH\]
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