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VIT Engineering VIT Engineering Solved Paper-2009

  • question_answer
    Electrons   with   a   kinetic   energy   of \[\underline{X}\]are evolved from the surface of a metal, when it is exposed to radiation of wavelength of 600 nm. The minimum amount of energy required to remove an electron from the metal atom is

    A)  \[\underline{X}\]

    B)  \[\Delta {{H}_{f}}(H)=218kJ/mol\]

    C)  \[H-H\]    

    D)  \[52.15\]

    Correct Answer: A

    Solution :

     \[{{109}^{o}}28\]  \[\underline{X}\]atoms KE of \[\underline{X}\] or KE of \[p\pi .d\pi \]atoms \[Xe{{O}_{3}}\] \[Xe{{O}_{4}}\]KE of 1 atom \[3:5\] \[25:9\] \[\Delta {{H}_{f}}(H)=218kJ/mol\] \[H-H\] Minimum amount of energy required to remove an electron from the metal ion (ie. Threshold energy) \[52.15\] \[911\] \[104\]


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