A) \[104\]
B) \[52153\]
C) \[Alkyne\xrightarrow[Lindlars\,\,catalyst]{{{H}_{2}}}A\xrightarrow{Ozonolysis}\underset{only}{\mathop{B}}\,\]
D) \[\xleftarrow[\Pr ocess]{Wac\ker }C{{H}_{2}}=C{{H}_{2}}\]
Correct Answer: B
Solution :
Average kinetic energy per molecule \[=\frac{3}{2}KT\] or \[=\frac{3}{2}\frac{R}{{{N}_{0}}}T\] \[=\frac{3}{2}\times \frac{8.314}{6.023\times {{10}^{23}}}\times 300\] \[=6.21\times {{10}^{-21}}J{{K}^{-1}}molecul{{e}^{-1}}\]
You need to login to perform this action.
You will be redirected in
3 sec
