A) 3
B) 2
C) \[2\sqrt{2}\]
D) \[3\sqrt{2}\]
Correct Answer: D
Solution :
Let A = (1, 0, 0), B = (0,1, 0) and C = (0, 0,1) Now, \[AB=\sqrt{{{(0-1)}^{2}}+{{(1-0)}^{2}}+{{0}^{2}}}=\sqrt{2}\] \[BC=\sqrt{{{0}^{2}}+{{(0-1)}^{2}}+{{(1-0)}^{2}}}=\sqrt{2}\] and \[CA=\sqrt{{{(1-0)}^{2}}+{{0}^{2}}+{{(0-1)}^{2}}}=\sqrt{2}\] \[\therefore \] Perimeter of triangle = AB + BC + CA \[=\sqrt{2}+\sqrt{2}+\sqrt{2}\] \[=3\sqrt{2}\]
You need to login to perform this action.
You will be redirected in
3 sec
