A) 1490, 1510
B) 1510,1490
C) \[\frac{1}{1490},\frac{1}{1510}\]
D) \[\frac{1}{1510},\frac{1}{1490}\]
Correct Answer: A
Solution :
Here \[{{f}_{c}}=1.5MHz=1500kHz,\,\,{{f}_{m}}=10kHz\] \[\therefore \] Low side-band frequency \[={{f}_{c}}-{{f}_{m}}=1500kHz-10kHz\] \[=1490kHz\] Upper side-band frequency \[={{f}_{c}}+{{f}_{m}}=1500kHz+10kHz\] \[=1510kHz\]You need to login to perform this action.
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