A) \[\frac{4}{3}T\]
B) \[\frac{8}{3}T\]
C) \[\frac{40}{3}T\]
D) \[\frac{80}{3}T\]
Correct Answer: B
Solution :
Magnetic field inside the cylindrical conductor \[{{B}_{in}}=\frac{{{\mu }_{0}}}{4\pi }\frac{2ir}{{{R}^{2}}}\] [R = radius opf cylinder, r = distance of observation point from axis of cylinder) Magnetic field outside the cylinder at a distance r from its axis \[{{B}_{in}}=\frac{{{\mu }_{0}}}{4\pi }\frac{2i}{r}\] \[\Rightarrow \]\[\frac{{{B}_{in}}}{{{B}_{out}}}=\frac{rr}{{{R}^{2}}}\]\[\Rightarrow \] \[\frac{10}{{{B}_{out}}}=\frac{\left[ R-\frac{R}{4} \right](R+4R)}{{{R}^{2}}}\] \[\Rightarrow \] \[{{B}_{out}}=\frac{8}{3}T\]You need to login to perform this action.
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