A) 140 T
B) 12.5 T
C) 1.4 T
D) 0.14 T
Correct Answer: B
Solution :
Current, \[i=qv\] \[B=\frac{{{\mu }_{0}}i}{2r}=\frac{{{\mu }_{0}}qv}{2r}\] \[=\frac{4\pi \times {{10}^{-7}}\times 1.6\times {{10}^{-19}}\times 6.6\times {{10}^{15}}}{2\times 0.53\times {{10}^{-10}}}\] \[=\frac{2\pi \times 1.6\times 6.6}{5.3}=12.513T\]
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