VIT Engineering VIT Engineering Solved Paper-2010

  • question_answer
    Two light rays having the same wavelength \[\lambda \] in vacuum are in phase initially. Then the first ray travels a path \[{{l}_{1}}\] through a medium of refractive index \[{{n}_{1}}\] while the second ray travels a path of length \[{{l}_{2}}\] through a median of refractive index\[{{n}_{2}}\].   The two waves are then combined to observe interference. The phase difference between the two waves is

    A)  \[\frac{2\pi }{\lambda }\left( {{l}_{2}}-{{l}_{1}} \right)\]

    B)  \[\frac{2\pi }{\lambda }\left( {{n}_{1}}{{l}_{1}}-{{n}_{2}}{{l}_{2}} \right)\]

    C)  \[\frac{2\pi }{\lambda }\left( {{n}_{2}}{{l}_{2}}-{{n}_{1}}{{l}_{1}} \right)\]

    D)  \[\frac{2\pi }{\lambda }\left( \frac{{{l}_{1}}}{{{n}_{1}}}-\frac{{{l}_{2}}}{{{n}_{2}}} \right)\]

    Correct Answer: B

    Solution :

    Optical path for 1st ray \[={{n}_{1}}{{l}_{1}}\] Optical path for 2nd ray \[={{n}_{2}}{{l}_{2}}\] Phase difference, \[\Delta \phi =\frac{2\pi }{\lambda }\Delta x\] \[=\frac{2\pi }{\lambda }({{n}_{1}}{{l}_{1}}-{{n}_{2}}{{l}_{2}})\]


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