A) n-propyl alcohol
B) Isopropyl alcohol
C) hert-butyl alcohol
D) sec-butyl alcohol
Correct Answer: A
Solution :
In Victor Meyers test, primary alcohols \[({{1}^{o}})\] (alcohols haying \[-C{{H}_{2}}OH\]) give red colour. The structures of the given compounds are [a] \[\underset{\underset{({{1}^{o}})}{\mathop{n-prooyl\,\,alcohol}}\,}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH}}\,\] [b] \[\underset{({{2}^{o}})}{\mathop{\underset{iso-propyl\,alcohol}{\mathop{\underset{OH}{\mathop{\underset{|}{\mathop{C{{H}_{3}}CH-C{{H}_{3}}}}\,}}\,}}\,}}\,\] [c] \[\underset{({{3}^{o}})}{\mathop{\underset{tert-butyl\,alcohol}{\mathop{\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{\underset{OH}{\mathop{\underset{|}{\mathop{C{{H}_{3}}-C-C{{H}_{3}}}}\,}}\,}}\,}}\,}}\,}}\,\] [d] \[\underset{({{2}^{o}})}{\mathop{\underset{\sec -butylalcohol}{\mathop{\underset{OH}{\mathop{\underset{|}{\mathop{C{{H}_{3}}CHC{{H}_{2}}C{{H}_{3}}}}\,}}\,}}\,}}\,\] Thus, n-propyl allcohol being \[{{1}^{o}}\] alcohol gives red colour in Victor-Meyers test.
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