A) 3
B) 6
C) 4
D) 5
Correct Answer: B
Solution :
Coordination number of \[Ni\] in \[{{[Ni{{({{C}_{2}}{{O}_{4}})}_{3}}]}^{4-}}\]is 6. This is because \[{{C}_{2}}O_{4}^{2-}\] (oxalate) is a bidentate ligand and thus, each coordinated with the central atom at two sites.You need to login to perform this action.
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