A) \[NaBr\]
B) \[NaOBr\]
C) \[B{{r}_{2}}\]
D) None of the above
Correct Answer: B
Solution :
\[NaOBr\] converts amide group \[(-CON{{H}_{2}})\]to amine group \[(-N{{H}_{2}})\]. \[C{{H}_{3}}CON{{H}_{2}}\xrightarrow{NaOBr}C{{H}_{3}}N{{H}_{2}}+N{{a}_{2}}C{{O}_{3}}\]
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