A) \[L{{i}_{0}}^{2}/2\]
B) \[{{B}^{2}}/2{{\mu }_{0}}\]
C) \[{{\mu }_{0}}{{B}^{2}}/2\]
D) \[{{\mu }_{0}}/2{{B}^{2}}\]
Correct Answer: B
Solution :
\[{{E}_{mag}}=\frac{{{B}^{2}}}{2{{\mu }_{0}}}\]
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