A) \[0.09\Omega \]
B) \[0.03\Omega \]
C) \[0.3\Omega \]
D) \[0.9\Omega \]
Correct Answer: A
Solution :
Shunt \[S=\frac{G{{I}_{g}}}{I-{{I}_{g}}}\] \[=\frac{0.8\times 1}{10-1}=\frac{0.81}{9}\Omega =0.09\Omega \]
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