VIT Engineering VIT Engineering Solved Paper-2011

  • question_answer
    A chemical reaction was carried out at 300 K and 280 K. The rate constants were found to be \[{{k}_{1}}\] and \[{{k}_{2}}\] respectively. Then

    A)  \[{{k}_{2}}=4{{k}_{1}}\]

    B)  \[{{k}_{2}}=2{{k}_{1}}\]

    C)  \[{{k}_{2}}=0.25{{k}_{1}}\]

    D)  \[{{k}_{2}}=0.5{{k}_{1}}\]

    Correct Answer: C

    Solution :

     Rate constant becomes double for every \[{{10}^{o}}\] rise in temperature. Hence, for \[{{20}^{o}}\] rise in temperature, rate constant will become four times. i.e., \[{{k}_{1}}=4{{k}_{2}}\] \[{{k}_{2}}=0.25{{k}_{1}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner