question_answer 67)

  Describe the activity that shows that a current-carrying conductor experiences a force perpendicular to its length and the external magnetic filed. How does Fleming's left-hand rule help us to find the direction of the force acting on the current-carrying conductor?

Answer:

  To show the force is exerted on a current carrying conductor placed in a strong magnetic  field . Materials Required A conducting rod (AB), connecting wires, horse shoe magnet, battery, switch and clamp stand. Procedure (i) Connect the conducting rod /6to the battery and key. (ii) Place a strong horse shoe magnet in such a way that the rod AB lines between the poles with magnetic field directed upwards, i.e., N-pole is vertically above the rod, (iii) Plug in the key. Observation A current-carrying rod AB experiences a force perpendicular to its length and the magnetic field. Based on above observation, it can be said that when a current carrying conductor is placed within a magnetic field, the conductor experiences deflection. Fleming's left hand rule explains the direction of displacement in this case. Let us assume that the current is moving in anticlockwise direction in the loops, It that case, the magnetic field would be in clockwise direction at the top of the loop. Moreover, it would be in anticlockwise direction at the bottom of the loop.