Answer:
(c) Electronic
configuration of Mg (atomic number 12) 2, 8, 2.
Electronic
configuration of Na (atomic number 11) 2, 8, 1.
Electronic
configuration of K (atomic number 19) 2, 8, 8, 1.
Electronic
configuration of Ca (atomic number 20) 2, 8, 8, 2.
From the
above electronic configurations, it is clear that K and Na will lose electron easily
to achieve stable configuration. But out of K and Na, K will lose electron more
easily because the force of attraction on valence electron of K is least among
the given.
In other
words, larger the atomic radius of an element more easily it can lose its
valence electron. Among all these, K has the largest atomic radius, therefore
it can lose its valence electron more easily.
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