Answer:
In \[B{{F}_{3}},B\], B is.\[s{{p}^{2}}\]-hybridized
and in \[N{{H}_{3}},N\] is \[s{{p}^{3}}\]hybridized. After the reaction, the
hybridization state of B changes to \[s{{p}^{3}}\]but that of nitrogen remains
the same.
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