Answer:
\[{{H}_{2}}S\]:
A = 2 + 6 = 8, N = 2 x 2 + 8 = 12,
S = N - A = 12 - 8 = 4 electrons shared
\[SiC{{l}_{4}}\]:\[A=4+4\times 7=32,N=8+8\times 4=40,\]
\[S=N-A=40-32=8\] electrons shared
\[Be{{F}_{2}}\]:
\[ClO_{3}^{-}\]: A = 7 + 6 x 3 + 1 = 26, N = 8 + 3 x 8 = 32,
S = N - A = 32 - 26 = 6 electrons shared
HCOOH : A = 18, N = 28,
S = N - A =28 -18 = 10 electrons shared
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