Answer:
p-block elements form acidic,
basic and amphoteric oxides. C, N, P, S, Cl, etc. (i.e., p-block elements) form
acidic oxides. They combine with water to form oxyacids.
\[C{{O}_{2}}+{{H}_{2}}O\to
\underset{\text{Carbonic}\,\text{acid}}{\mathop{{{H}_{2}}C{{O}_{3}}}}\,\]
\[{{N}_{2}}{{O}_{5}}+{{H}_{2}}O\to
\underset{Nitric\,acid}{\mathop{2HN{{O}_{3}}}}\,\]
\[{{P}_{2}}{{O}_{5}}+3{{H}_{2}}O\to
\underset{Orthophosphoric\,acid}{\mathop{2{{H}_{3}}P{{O}_{4}}}}\,\]
\[S{{O}_{3}}+{{H}_{2}}O\to
\underset{Sulphuric\,acid}{\mathop{{{H}_{2}}S{{O}_{4}}}}\,\]
\[C{{l}_{2}}{{O}_{7}}+{{H}_{2}}O\to
\underset{Perchloric\,acid}{\mathop{2HCl{{O}_{4}}}}\,\]
Al, Sb, Pb, etc. (i.e., p-block
elements) form amphoteric oxides. These oxides react with acids and bases both.
\[A{{1}_{2}}{{O}_{3}}\text{
}+6HCl\to \text{ }2A1C{{1}_{3}}\text{ }+3{{H}_{2}}O\]
\[A{{l}_{2}}{{O}_{3}}+2NaOH\to
2NaAl{{O}_{2}}+{{H}_{2}}O\]
\[S{{b}_{2}}{{O}_{3}}\text{
}+6HCl\text{ }\to \text{ }2SbC{{l}_{3}}\text{ }+3{{H}_{2}}O\]
\[S{{b}_{2}}{{O}_{3}}+6NaOH\to
\text{ }N{{a}_{3}}Sb{{O}_{3}}+3{{H}_{2}}O\]
\[PbO+{{H}_{2}}S{{O}_{4}}\text{
}\to \text{ }PbS{{O}_{4}}\text{ }+{{H}_{2}}O\]
\[PbO+\text{ }2NaOH\to \text{
}N{{a}_{2}}Pb{{O}_{2}}\text{ }+\text{ }{{H}_{2}}O\]
The oxides of In and Tl (p-block
elements) form basic oxides.
\[I{{n}_{2}}{{O}_{3}}+3{{H}_{2}}S{{O}_{4}}\to
I{{n}_{2}}{{\left( S{{O}_{4}} \right)}_{3}}+3{{H}_{2}}O\]
\[\text{T}{{\text{1}}_{\text{2}}}\text{O
+ }{{\text{H}}_{\text{2}}}\text{O}\to \text{2T1OH}\]
\[T{{l}_{2}}{{O}_{3}}\text{
}+3{{H}_{2}}S{{O}_{4}}\text{ }\to \text{ }T{{l}_{2}}{{\left( S{{O}_{4}}
\right)}_{3}}+3{{H}_{2}}O\]
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