Answer:
Let oxidation state of \[\text{Al}\]
is x
i.e., \[{{[AlCl{{({{H}_{2}}O)}_{5}}]}^{2+}}\]
or \[x+1+5\times
0=+2\]
so,
\[x=+3\]
It is a complex compound in which coordinate covalency of \[\text{Al}\]
is '6.
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