Answer:
(b)\[N{{H}_{4}}N{{O}_{3}},\]
\[\underset{\begin{smallmatrix}
x\,+\,4\,=\,+\,1
\\
x\,=\,-3
\end{smallmatrix}}{\mathop{NH_{4}^{+}}}\,\] \[\underset{\begin{smallmatrix}
x\,-\,6\,=\,-1
\\
x\,=\,+5
\end{smallmatrix}}{\mathop{NO_{3}^{-}}}\,\]
Thus, both nitrogen atoms are in
different oxidation states.
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