Answer:
(a) \[N{{a}_{2}}{{S}_{2}}{{O}_{3}}\]
\[+2+2x-6=0\]
\[x=+2\]
(b) \[\overset{+}{\mathop{N}}\,a\overset{\overset{-2}{\mathop{-}}\,}{\mathop{O}}\,-\underset{\underset{\underset{-2}{\mathop{O}}\,}{\mathop{||}}\,}{\overset{\overset{\overset{-2}{\mathop{O}}\,}{\mathop{||}}\,}{\mathop{{{S}^{x}}}}}\,-\overset{0}{\mathop{S}}\,-\overset{0}{\mathop{S}}\,-\underset{\underset{\underset{-2}{\mathop{O}}\,}{\mathop{||}}\,}{\overset{\overset{\overset{-2}{\mathop{O}}\,}{\mathop{||}}\,}{\mathop{S}}}\,-\overset{(-2)}{\mathop{\overset{-}{\mathop{O}}\,N\overset{+}{\mathop{a}}\,}}\,\]
\[2x+2-12=0\]
\[x=+5\]
Two sulphur atoms are in (+5) and
remaining two are in zero oxidation state.
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