Answer:
(i)\[C{{r}_{2}}O_{7}^{2-}+{{H}^{+}}+{{I}^{-}}\to
C{{r}^{3+}}+{{I}_{2}}+{{H}_{2}}O\]
Half equation:
\[C{{r}_{2}}O_{7}^{2-}+14{{H}^{+}}+6{{e}^{-}}\to
2C{{r}^{3+}}+7{{H}_{2}}O\](Reduction)
Half equation:
\[\frac{\frac{[2{{I}^{-}}\to
{{I}_{2}}+2{{e}^{-}}]\times
3(Oxidation)}{C{{r}_{2}}O_{7}^{2-}+6{{I}^{-}}+14{{H}^{+}}\to 2C{{r}^{3+}}+3{{I}_{2}}+7{{H}_{2}}O}}{{}}\]
(Balanced equation)
(ii) \[C{{r}_{2}}O_{7}^{2-}+F{{e}^{2+}}+{{H}^{+}}\to
C{{r}^{3+}}+F{{e}^{3+}}+{{H}_{2}}O\]
Half equation:
\[C{{r}_{2}}O_{7}^{2-}+14{{H}^{+}}+6{{e}^{-}}\to
2C{{r}^{3+}}+7{{H}_{2}}O\]
(Reduction)
Half equation:
\[\frac{\frac{[F{{e}^{2+}}\to
F{{e}^{3+}}+{{e}^{-}}]\times
6~(Oxidation)}{C{{r}_{2}}O_{7}^{2-}+6F{{e}^{2+}}+14{{H}^{+}}\to
2C{{r}^{3+}}+6F{{e}^{3+}}+7{{H}_{2}}O}}{{}}\]
(Balanced equation)
(iii) \[MnO_{4}^{-}+SO_{3}^{2-}+{{H}^{+}}\to
M{{n}^{+}}+SO_{4}^{2-}+{{H}_{2}}O\]
Half equation:
\[[MnO_{4}^{-}+SO_{3}^{2-}+{{H}^{+}}\to
M{{n}^{2+}}+SO_{4}^{2-}+{{H}_{2}}O]\]
(Reduction)
Half equation:
\[\frac{\frac{[SO_{3}^{2-}+{{H}_{2}}O\to
SO_{4}^{2-}+2{{H}^{+}}+2{{e}^{-}}]\times 5(Oxidation)}{2MnO_{4}^{-}+5SO_{3}^{2-}+6{{H}^{+}}\to
2M{{n}^{2+}}+5SO_{4}^{2-}+3{{H}_{2}}O}}{{}}\]
(Balanced equation)
(iv)\[MnO_{4}^{-}+{{H}^{+}}+B{{r}^{-}}\to
M{{n}^{2+}}+B{{r}_{2}}+{{H}_{2}}O\]
Half equation:
\[[MnO_{4}^{-}+8{{H}^{+}}+5{{e}^{-}}\to
M{{n}^{2+}}+4{{H}_{2}}O]\times 2\](Reduction)
Half equation:
\[\frac{\frac{[2B{{r}^{-}}\to
B{{r}_{2}}+2{{e}^{-}}]\times
(Oxidation)}{2MnO_{4}^{-}+10B{{r}^{-}}+16{{H}^{+}}\to
2M{{n}^{2+}}+5B{{r}_{2}}+8{{H}_{2}}O}}{{}}\]
(Balanced equation)
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