Answer:
Beryllium
Be forms amphoteric oxide, \[BeO\]and
a water soluble\[BeS{{O}_{4}}\].
\[\underset{Acidic}{\mathop{BeO}}\,+2NaOH\to
N{{a}_{2}}Be{{O}_{2}}+{{H}_{2}}O\]
\[\underset{Basic}{\mathop{BeO}}\,+2HCl\to
BeC{{l}_{2}}+{{H}_{2}}O\]
\[BeS{{O}_{4}}\]is soluble in
water as its hydration energy is more than lattice energy.
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