question_answer 84)

  1 mol of a mono atomic gas is expanded from state (1) to state (2) as shown in figure. Calculate the work done for the expansion of gas from state (1) to state (2) at 298 K.  

Answer:

  In isothermal condition \[{{P}_{1}}{{V}_{1}}={{P}_{2}}{{V}_{2}}\] \[\frac{{{V}_{2}}}{{{V}_{1}}}=\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{2}{1}=2\] \[w=2.303nRT\,\log \,\left( \frac{{{P}_{1}}}{{{P}_{2}}} \right)\] \[=2.303\times 1\times 8.314\times 298{{\log }_{10}}2\] \[=1717.63J\] \[{{w}_{\exp }}=-1717.63J\]