Answer:
In case of two heterozygous parents, showing linkage,
result will be:
Parents:
BpLl X BpLl Genotype
(Blue long) (Blue long) Phenotype
In all
the combinations may show parental characters as the genes are completely
linked. With all possible genotypes in ,
progeny may exhibit blue long type of phenotype in above case. However in case
of incomplete linkage, parental combinations will be more and new combinations
will be less in number.
You need to login to perform this action.
You will be redirected in
3 sec