Answer:
Since
aromatic compound 'A' (MF )
gives positive 2, 4-DNP test, it must be an aldehyde or a ketone.
(ii) Since compound 'A' does not give Tollens' test or Fehling?s test,
therefore, 'A' must be a ketone.
(iii) Since compound 'A' on treatment with , gives yellow ppt. of
compound 'B', therefore, compound ?B? must be iodoform and the ketone 'A' must
be a methyl ketone.
(iv) Since methyl ketone 'A' on drastic oxidation with
KMn04 gives a carboxylic acid 'C'therefore, 'C' must be
benzole acid and compound 'A' must be acetophenone
(v) If 'A' is acetophenone, then all the reactions
described above may be explained as follows
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