formation of amide by
reacting with 
Hofmann bromamide
reaction i.e., reaction with 
.
(ii) Partial hydrolysis, Hofmann
bromamide reaction.
(iii) Chlorination (reaction
with 
or 
) substituting 
by CN
(using alc. KCN, hydrolysis.
(iv) Reaction with 
,
oxidation, amide formation (by reaction with),then amine formation (i.e.,
Hofmann brornamide reaction).
(v) Reduction (by 
),
iodination cyanide formation, hydrolysis.
(vi) Alcohol formation i.e.,
reaction with 
iodination. Cyanide
formation reduction.
(vii) Reduction into
by 
carbylamine
reaction, reduction.
(viii) Amide formation (reaction with ), Hofmann?sbromamide
reaction, reaction with nitrous acid, oxidation.
Answer:
(i)Ethanoic acid into methanamine
(ii) Hexane nitrile to
1-aminopentane
(iii) Methanol to ethanoic acid
(iv) Ethanamine to methanamine
(v) Ethanoic acid into
propanoic acid
(vi) Methanamine to ethanamine
(vii)Nitromethane into dimethyl
amine
(viii) Propanoic acid into
ethanoic acid
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