question_answer 15)

A raction is second order with respect to a reactant. How is the rate of reaction affected if the concentration of the reactant is (i) doubled (ii) reduced to half?

Answer:

r = k [A]2 (i) When concentration is doubled, then the new rate r? = k [2A]2                                                                                           ?.(ii) Divide (ii) by (i) Thus, rate of reaction becomes four times. (ii) When concentration of the reactant is reduced to , then the new rate. Divide (ii) by (i)             Thus, rate of reaction is reduced to one-fourth.