2. Free Ncert Solutions
  3. 12th Class
  4. Chemistry
  5. Chemical Kinetics / रासायनिक बलगतिकी

12th Class Chemistry Chemical Kinetics / रासायनिक बलगतिकी

  • question_answer 35)
    The decomposition of a hydrocarbon follows the equation: k = (4.5 × 1011 s?1) e?28000K/T. Calculate the energy of activation (Ea).  

    Answer:

    According to Arrhenius equation According to given data : On comparison; Or Ea = (28000 K) × (8.314 K?1 mol?1)    = 232792 J mol?1.  


You need to login to perform this action.
You will be redirected in 3 sec spinner